pyqt5与matplotlib的完美结合实例

Python  /  管理员 发布于 5年前   441

具体用到了matplotlib.backends.backend_qt5agg.FigureCanvasQTAgg

直接上代码(这里给出的只是一个简单的框架，告诉你怎么去写)：

# -*- coding: utf-8 -*-'''TODO:LQD'''import sysimport numpy as npimport matplotlib.pyplot as pltfrom matplotlib.backends.backend_qt5agg import FigureCanvasQTAgg as FCfrom PyQt5.QtWidgets import QApplication, QPushButton, QMainWindow, QVBoxLayout, QWidget  class QtDraw(QMainWindow):  flag_btn_start = True   def __init__(self):    super(QtDraw, self).__init__()    self.init_ui()   def init_ui(self):    self.resize(800, 600)    self.setWindowTitle('PyQt5 Draw')     # TODO:这里是结合的关键    self.fig = plt.Figure()    self.canvas = FC(self.fig)    self.btn_start = QPushButton(self)    self.btn_start.setText('draw')    self.btn_start.clicked.connect(self.slot_btn_start)     widget = QWidget()    layout = QVBoxLayout()    layout.addWidget(self.canvas)    layout.addWidget(self.btn_start)    widget.setLayout(layout)    self.setCentralWidget(widget)   def slot_btn_start(self):    try:      ax = self.fig.add_subplot(111)      x = np.linspace(0, 100, 100)      y = np.random.random(100)      ax.cla() # TODO:删除原图，让画布上只有新的一次的图      ax.plot(x, y)      self.canvas.draw() # TODO:这里开始绘制    except Exception as e:      print(e)  def ui_main():  app = QApplication(sys.argv)  w = QtDraw()  w.show()  sys.exit(app.exec_())  if __name__ == '__main__':  ui_main()

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