Shell使用Epoch进行日期时间转换和计算的几个小函数

技术  /  管理员 发布于 7年前   349

核心代码

当你遇到一个date命令不给力的系统时，可以试试这几个小函数。#日期转天数function date2days {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}date2days `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#天数转日期function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d-%02d-%02d\n",yy,mm,dd)  }'}days2date 14839#日期转分钟function date2minutes {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*1440+$4*60+$5    print j  }'}date2minutes `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#分钟转日期function minutes2date {  echo "$1" | awk '{    i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);    a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d-%02d-%02d %02d:%02d\n",yy,mm,dd,hh,nn)  }'}minutes2date 21369299#日期转秒数function date2seconds {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*86400+$4*3600+$5*60+$6    print j  }'}date2seconds `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#秒数转日期function seconds2date {  echo "$1" | awk '{    i=$1; ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);    a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d-%02d-%02d %02d:%02d:%02d\n",yy,mm,dd,hh,nn,ss)  }'}seconds2date 1282157959#日期转毫秒function date2milliseconds {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*86400+$4*3600+$5*60+$6    printf ("%d%s\n",j,$7)  }'}date2milliseconds `echo "2010-08-18 18:59:19.073" | sed 's/-/ /g;s/:/ /g;s/\./ /g'`#毫秒转日期function milliseconds2date {  echo "$1" | awk '{    i=$1; ms=i%1000; i=int(i/1000); ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);    a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d-%02d-%02d %02d:%02d:%02d.%03d\n",yy,mm,dd,hh,nn,ss,ms)  }'}milliseconds2date 1282157959073

应用实例：

计算今天的N天之后的日期

#!/bin/bashfunction date2days {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d%02d%02d\n",yy,mm,dd)  }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`N=5let days-=$Ndays2date $days

计算某天的N天之后的日期

#!/bin/bashfunction date2days {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d%02d%02d\n",yy,mm,dd)  }'}year=2010; month=01; day=20days=`date2days $year $month $day`let days+=5days2date $days

计算上一个星期的全部日期

#!/bin/bashfunction date2days {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d%02d%02d\n",yy,mm,dd)  }'}function date2week {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7;    print dow  }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`week=`date2week $year $month $day`let dateEnd=$days-$week-1let dateBegin=$dateEnd-6for ((i=$dateBegin;i<=$dateEnd;i++)); do  days2date $idone

日期时间转换成毫秒

function date2milliseconds {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*86400+$4*3600+$5*60+$6    print j$7  }'}date2milliseconds `echo "2010-08-18 18:59:19.073" | /usr/xpg4/bin/awk -F'[:.-]+' '$1=$1'`

日期时间转换成秒

function date2seconds {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*86400+$4*3600+$5*60+$6    print j  }'}date2seconds `echo "2010-07-21 00:00:00" | sed 's/-/ /g;s/:/ /g'`

判断一个数字是否为合法日期

function date2days {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d%02d%02d\n",yy,mm,dd)  }'}num1=20105050num2=20101001arg1=`echo "$num1" | sed -r 's/(....)(..)(..)/\1 \2 \3/g'`arg2=`echo "$num2" | sed -r 's/(....)(..)(..)/\1 \2 \3/g'`days1=`date2days $arg1`date1=`days2date $days1`days2=`date2days $arg2`date2=`days2date $days2`[ "$num1" -eq "$date1" ] && echo "$num1 is valid date" || echo "$num1 is invalid date"[ "$num2" -eq "$date2" ] && echo "$num2 is valid date" || echo "$num2 is invalid date"

计算10分钟之前的时间

function date2minutes {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    j=j*1440+$4*60+$5    print j  }'}function minutes2date {  echo "$1" | awk '{    i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24);    a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d-%02d-%02d %02d:%02d\n",yy,mm,dd,hh,nn)  }'}now=`date "+%Y-%m-%d %H:%M" | sed 's/-/ /g;s/:/ /g'`minutes=`date2minutes $now`let minutes-=10minutes2date $minutes

计算指定日期和当前系统日期之家相差多少天

#!/bin/bashfunction date2days {  echo "$*" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}echo "Enter your date:"read inputInpuDays=$(date2days ${input:0:4} ${input:4:2} ${input:6:2})SysDays=$(date2days `date +"%Y %m %d"`)let result=$InpuDays-$SysDaysecho $result

#./test.shEnter your date:2011060525

上个星期周一的日期

#!/bin/bashfunction date2days {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633;    print j  }'}function days2date {  echo "$1" | awk '{    a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a;     d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153);    dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10);    printf ("%4d%02d%02d\n",yy,mm,dd)  }'}function date2week {  echo "$1 $2 $3" | awk '{    z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3;    dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7;    print dow  }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`week=`date2week $year $month $day`let date=$days-$week-7days2date $date