shell打印给定日期的日历

技术  /  管理员 发布于 7年前   127

学习shell有一段时间了，一直没有机会练手，看到同事发了一张照片，控制台显示了当月的日历，是用Python实现的，感觉挺好玩，所以准备用shell来实现一个，搞了一下午，终于搞定。

打印本月的日期

#! /bin/bash#设置字体颜色tiffcolor="\033[0;35m"menucolor="\033[0;33m"todaycolor="\033[0;35;44m"start="\033[0m"#计算各个日期month=`date +%m`day=`date +%d`year=`date +%Y`weekday=`date -d "$year-$month-01" +%w`nextmonth=`expr $month + 1`today=`date +%d`#计算本月有多少天differ=$(( ($(date -d "$year-$nextmonth-01" +%s) - $(date +%s))/(24*60*60) )) days=`expr $differ + $day`#打印标题echo -en "${menucolor}"echo -en "\t  $year $month\n"echo "SUN MON TUE WEN THU FRI SAT"echo -en "${start}"#打印空格if [ $weekday -ne 0 ];thenfor((i=1;i<=$weekday;i++))do  echo -n "  "  echo -n " "donefi#打印日期for((i=1;i<=$days;i++))do  printf "%s" " "  echo -en "${tiffcolor}"  #今天高亮显示    if [ $today -eq $i ];then      echo -en "${todaycolor}"    fi  printf "%2d" $i  echo -en "${start}"  echo -en " "  if [ $((($weekday+$i)%7)) == 0 ];then    echo ""  fi#  printf "%3d " $idoneecho ""

执行结果：

扩展：给定任意日期，打印当月的日期

#! /bin/bash#date=$1tiffcolor="\033[0;35m"menucolor="\033[0;33m"todaycolor="\033[0;35;44m"start="\033[0m"if [ $# -ne 1 ];then  echo "plz input the date"  exit 1fidate=$1count=`echo $date |grep -o '-'|wc -l`if [ $count -ne 2 ];then  echo "plz input correct date"  exit 1fiyear=`echo $date|cut -d "-" -f 1`month=`echo $date|cut -d "-" -f 2`day=`echo $date|cut -d "-" -f 3`expr $year + $month + $day + 0 &>/dev/nullif [ $? -ne 0 ];then  echo "plz input a correct date"  exit 1elif [ $month -gt 12 -o $month -eq 0 ];then  echo "plz input the month between 1 and 12"  exit 1elif [ $day -gt 31 -o $day -eq 0 ];then  echo "plz input the day between 1 and 31"  exit 1fi#nextmonth=$(( $month + 1))#month=`date -d "$date" +%m`#day=`date -d "$date" +%d`#year=`date -d "$date" +%Y`weekday=`date -d "$year-$month-01" +%w`if [ $month -eq 12 ];then  newmonth=1  newyear=`expr $year + 1`else  newyear=$year  #nextmonth= expr $month + 1  newmonth=`expr $month + 1`fidays=$(( ($(date -d "${newyear}-${newmonth}-01" +%s) - $(date -d "$year-$month-01" +%s))/(24*60*60) )) #echo $daysecho -en "${menucolor}"echo -en "\t  $year $month\n"echo "SUN MON TUE WEN THU FRI SAT"echo -en "${start}"if [ $weekday -ne 0 ];thenfor((i=1;i<=$weekday;i++))do  echo -n "  "  echo -n " "donefifor((i=1;i<=$days;i++))do  printf "%s" " "  echo -en "${tiffcolor}"    if [ $day -eq $i ];then      echo -en "${todaycolor}"    fi  printf "%2d" $i  echo -en "${start}"  echo -en " "  if [ $((($weekday+$i)%7)) == 0 ];then    echo ""  fi#  printf "%3d " $idoneecho ""

执行结果：

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