Dos下获取系统时间的代码

技术  /  管理员 发布于 7年前   140

复制代码 代码如下: 
rem DOS get current time 
rem ======================= 
rem get yyyy/mm/dd 
set mydate=%DATE:~0,10% 
echo %mydate% 
rem ======================= 
rem get yyyy 
set yyyy=%DATE:~0,4% 
echo %yyyy% 
rem ======================= 
rem get mm 
set mm=%DATE:~5,2% 
echo %mm% 
rem ======================= 
rem get dd 
set dd=%DATE:~8,2% 
echo %dd% 
rem ======================= 
rem get yyyy-mm-dd 
set curdate=%yyyy%-%mm%-%dd% 
echo %curdate%


其实bat中获取时间就是利用截取日期字符串的方法

DOS下有字符处理的方法的，总结如下：

在这个日期格式下：”2013-07-22 星期一”， 这个%DATE:~0,10%得到的是2013-07-22
说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。

输出：

C:\Documents and Settings\Administrator>rem DOS get current time
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy/mm/dd
C:\Documents and Settings\Administrator>set mydate=2013-07-22
C:\Documents and Settings\Administrator>echo 2013-07-22
2013-07-22
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy
C:\Documents and Settings\Administrator>set yyyy=2013
C:\Documents and Settings\Administrator>echo 2013
2013
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get mm
C:\Documents and Settings\Administrator>set mm=07
C:\Documents and Settings\Administrator>echo 07
07
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get dd
C:\Documents and Settings\Administrator>set dd=22
C:\Documents and Settings\Administrator>echo 22
22
C:\Documents and Settings\Administrator>rem =======================
C:\Documents and Settings\Administrator>rem get yyyy-mm-dd
C:\Documents and Settings\Administrator>set curdate=2013  -07  -22
C:\Documents and Settings\Administrator>echo 2013  -07  -22
2013  -07  -22
C:\Documents and Settings\Administrator>