sqlserver实现树形结构递归查询(无限极分类)的方法

数据库  /  管理员 发布于 5年前   383

SQL Server 2005开始，我们可以直接通过CTE来支持递归查询,CTE即公用表表达式

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公用表表达式（CTE），是一个在查询中定义的临时命名结果集将在from子句中使用它。每个CTE仅被定义一次（但在其作用域内可以被引用任意次），并且在该查询生存期间将一直生存。可以使用CTE来执行递归操作。创建的语法是：

with <name of you cte>(<column names>)as(<actual query>)select * from <name of your cte>

1、生成数据

--菜单目录结构表 create table tb_menu(  id int not null, --主键id title varchar(50), --标题  parent int --parent id ); --父菜单 insert into tb_menu(id, title, parent) values(1, '父菜单1',null); insert into tb_menu(id, title, parent) values(2, '父菜单2',null); insert into tb_menu(id, title, parent) values(3, '父菜单3',null); insert into tb_menu(id, title, parent) values(4, '父菜单4',null); insert into tb_menu(id, title, parent) values(5, '父菜单5',null); --一级菜单 insert into tb_menu(id, title, parent) values(6, '一级菜单6',1); insert into tb_menu(id, title, parent) values(7, '一级菜单7',1); insert into tb_menu(id, title, parent) values(8, '一级菜单8',1); insert into tb_menu(id, title, parent) values(9, '一级菜单9',2); insert into tb_menu(id, title, parent) values(10, '一级菜单10',2); insert into tb_menu(id, title, parent) values(11, '一级菜单11',2); insert into tb_menu(id, title, parent) values(12, '一级菜单12',3); insert into tb_menu(id, title, parent) values(13, '一级菜单13',3); insert into tb_menu(id, title, parent) values(14, '一级菜单14',3); insert into tb_menu(id, title, parent) values(15, '一级菜单15',4); insert into tb_menu(id, title, parent) values(16, '一级菜单16',4); insert into tb_menu(id, title, parent) values(17, '一级菜单17',4); insert into tb_menu(id, title, parent) values(18, '一级菜单18',5); insert into tb_menu(id, title, parent) values(19, '一级菜单19',5); insert into tb_menu(id, title, parent) values(20, '一级菜单20',5); --二级菜单 insert into tb_menu(id, title, parent) values(21, '二级菜单21',6); insert into tb_menu(id, title, parent) values(22, '二级菜单22',6); insert into tb_menu(id, title, parent) values(23, '二级菜单23',7); insert into tb_menu(id, title, parent) values(24, '二级菜单24',7); insert into tb_menu(id, title, parent) values(25, '二级菜单25',8); insert into tb_menu(id, title, parent) values(26, '二级菜单26',9); insert into tb_menu(id, title, parent) values(27, '二级菜单27',10); insert into tb_menu(id, title, parent) values(28, '二级菜单28',11); insert into tb_menu(id, title, parent) values(29, '二级菜单29',12); insert into tb_menu(id, title, parent) values(30, '二级菜单30',13); insert into tb_menu(id, title, parent) values(31, '二级菜单31',14); insert into tb_menu(id, title, parent) values(32, '二级菜单32',15); insert into tb_menu(id, title, parent) values(33, '二级菜单33',16); insert into tb_menu(id, title, parent) values(34, '二级菜单34',17); insert into tb_menu(id, title, parent) values(35, '二级菜单35',18); insert into tb_menu(id, title, parent) values(36, '二级菜单36',19); insert into tb_menu(id, title, parent) values(37, '二级菜单37',20);  --三级菜单 insert into tb_menu(id, title, parent) values(38, '三级菜单38',21); insert into tb_menu(id, title, parent) values(39, '三级菜单39',22); insert into tb_menu(id, title, parent) values(40, '三级菜单40',23); insert into tb_menu(id, title, parent) values(41, '三级菜单41',24); insert into tb_menu(id, title, parent) values(42, '三级菜单42',25); insert into tb_menu(id, title, parent) values(43, '三级菜单43',26); insert into tb_menu(id, title, parent) values(44, '三级菜单44',27); insert into tb_menu(id, title, parent) values(45, '三级菜单45',28); insert into tb_menu(id, title, parent) values(46, '三级菜单46',28); insert into tb_menu(id, title, parent) values(47, '三级菜单47',29); insert into tb_menu(id, title, parent) values(48, '三级菜单48',30); insert into tb_menu(id, title, parent) values(49, '三级菜单49',31); insert into tb_menu(id, title, parent) values(50, '三级菜单50',31); commit; 

2.查找所有上级节点

--查询树状结构某节点(44)的上级所有根节点  with cte_parent(id,title,parent)  as  (    --起始条件    select id,title,parent    from tb_menu    where id = 44  --列出子节点查询条件    union all    --递归条件    select a.id,a.title,a.parent    from tb_menu a    inner join     cte_parent b     --执行递归，这里就要理解下了     on a.id=b.parent   )  select * from cte_parent; 

3.查找下级节点带level

--查询树状结构某节点下的所有子节点(  with cte_child(id,title,parent,level)  as  (    --起始条件    select id,title,parent,0 as level    from tb_menu    where id = 6--列出父节点查询条件    union all    --递归条件    select a.id,a.title,a.parent,b.level+1    from tb_menu a    inner join     cte_child b    on ( a.parent=b.id)   )  select * from cte_child; 

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