如何通过SQL找出2个表里值不同的列的方法

数据库  /  管理员 发布于 6年前   612

以下有两个表，他们的结构完全相同，请通过SQL找出值不同的列。

Student_1

NAME	AGE	SCORE
peter	26	100
jack	25	96
daniel	26	48
bark	21	69

 

 

Student_2

NAME	AGE	SCORE
peter	26	89
jack	25	96
daniel	26	48
bark	21	69

 

方法一 -- NOT EXISTS：

复制代码 代码如下:
SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
  (SELECT *
  FROM Student_2 S2
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  )
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
  (SELECT *
  FROM STUDENT_1 S1
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  );

方法二 -- MINUS
复制代码 代码如下:
(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)

方法三 -- HAVING GROUP BY
复制代码 代码如下:
SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;