获取MSSQL 表结构中字段的备注、主键等信息的sql

数据库  /  管理员 发布于 5年前   304

1、MSSQL2000
复制代码 代码如下:
SELECT
表名 = case when a.colorder=1 then d.name else '' end,
表说明 = case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序号 = a.colorder,
字段名 = a.name,
标识 = case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
主键 = case when exists(SELECT 1 FROM sysobjects where xtype='PK' and parent_obj=a.id and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid))) then '√' else '' end,
类型 = b.name,
占用字节数 = a.length,
长度 = COLUMNPROPERTY(a.id,a.name,'PRECISION'),
小数位数 = isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
允许空 = case when a.isnullable=1 then '√'else '' end,
默认值 = isnull(e.text,''),
字段说明 = isnull(g.[value],'')
FROM
syscolumns a
left join
systypes b
on
a.xusertype=b.xusertype
inner join
sysobjects d
on
a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join
syscomments e
on
a.cdefault=e.id
left join
sysproperties g
on
a.id=g.id and a.colid=g.smallid
left join
sysproperties f
on
d.id=f.id and f.smallid=0
where
d.name='FI_dept' --如果只查询指定表,加上此条件
order by

a.id,a.colorder


2、MSSQL2005

use test--数据库
go
--2005实现字段属性统计(2000里的系统表sysproperties描述表、字段不存在，2005里用sys.extended_properties视图替代)
select
[表名]=c.Name,
[表说明]=isnull(f.[value],''),
[列名]=a.Name,
[列序号]=a.Column_id,
[标识]=case when is_identity=1 then '√' else '' end,
[主键]=case when exists(select 1 from sys.objects where parent_object_id=a.object_id and type=N'PK' and name in
(select Name from sys.indexes where index_id in
(select indid from sysindexkeys where and colid=a.column_id)))
then '√' else '' end,
[类型]=b.Name,
[字节数]=case when a.[max_length]=-1 and b.Name!='xml' then 'max/2G'
when b.Name='xml' then ' 2^31-1字节/2G'
else rtrim(a.[max_length]) end,
[长度]=ColumnProperty(a.object_id,a.Name,'Precision'),
[小数]=isnull(ColumnProperty(a.object_id,a.Name,'Scale'),0),
[是否榭]=case when a.is_nullable=1 then '√' else '' end,
[列说明]=isnull(e.[value],''),
[默认值]=isnull(d.text,'')
from
sys.columns a
left join
sys.types b on a.user_type_id=b.user_type_id
inner join
sys.objects c on a.object_id=c.object_id and c.Type='U'
left join
syscomments d on a.default_object_id=d.ID
left join
sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.Column_id and e.class=1
left join
sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1
[/code]
结果：