Django框架使用内置方法实现登录功能详解

框架(架构)  /  管理员 发布于 7年前   161

本文实例讲述了Django框架使用内置方法实现登录功能。分享给大家供大家参考，具体如下：

一 内置登录退出思维导图

二 Django内置登录方法

1 位置

2 源码

@deprecate_current_app@sensitive_post_parameters()@csrf_protect@never_cache# 视图函数要渲染的模板位置（registration/login.html）def login(request, template_name='registration/login.html',     redirect_field_name=REDIRECT_FIELD_NAME,     authentication_form=AuthenticationForm,     extra_context=None, redirect_authenticated_user=False):  """  Displays the login form and handles the login action.  """  redirect_to = request.POST.get(redirect_field_name, request.GET.get(redirect_field_name, ''))  if redirect_authenticated_user and request.user.is_authenticated:    redirect_to = _get_login_redirect_url(request, redirect_to)    if redirect_to == request.path:      raise ValueError(        "Redirection loop for authenticated user detected. Check that "        "your LOGIN_REDIRECT_URL doesn't point to a login page."      )    return HttpResponseRedirect(redirect_to)  elif request.method == "POST":    form = authentication_form(request, data=request.POST)    if form.is_valid():      auth_login(request, form.get_user())      return HttpResponseRedirect(_get_login_redirect_url(request, redirect_to))  else:    form = authentication_form(request)  current_site = get_current_site(request)  context = {    'form': form,    redirect_field_name: redirect_to,    'site': current_site,    'site_name': current_site.name,  }  if extra_context is not None:    context.update(extra_context)  return TemplateResponse(request, template_name, context)

三 实战一 

1 编辑mysite/account/urls.py

from django.conf.urls import urlfrom . import viewsfrom django.contrib.auth import views as auth_viewsurlpatterns = [  # 自定义登录  # url(r'^login/$', views.user_login, name='user_login'),  # django内置的登录  url(r"^login/$", auth_views.login, name="user_login"),]

2 因为默认的模板位置为registration/login.html，因此我们创建该文档如下：

{% extends "base.html" %}{% block title %}登录{% endblock %}{% block content %}<div class="row text-center vertical-middle-sm"> <h1>登录</h1> <p>请输入用户名和密码</p>  <!--用具体的URL指明了数据的POST目标--> <form class="form-horizontal" action="{% url 'account:user_login' %}" method="post"> {% csrf_token %}    <!--每个表单元素在一对P标签内-->    <!--{{ form.as_p }}-->    <!--使用Bootstrap样式使得表单更美丽-->    <div class="form-group">  <label for="{{ form.username.id_for_label }}" class="col-md-5 control-label" style="color:red"><span class="glyphicon glyphicon-user"></span>Username</label>  <div class="col-md-6 text-left">{{ form.username }}</div> </div> <div class="form-group">  <label for="{{ form.password.id_for_label }}" class="col-md-5 control-label" style="color:blue"><span class="glyphicon glyphicon-floppy-open"></span>Password</label>  <div class="col-md-6 text-left">{{ form.password }}</div> </div> <input type="submit" value="Login"> </form></div>{% endblock %}

3 修改mysite/mysite/settings.py

# 登录后重定向到http://localhost:8000/blog/页面LOGIN_REDIRECT_URL = '/blog/'

4 测试

四 实战二

1 编辑mysite/account/urls.py

from django.conf.urls import urlfrom . import viewsfrom django.contrib.auth import views as auth_viewsurlpatterns = [  # 自定义登录  # url(r'^login/$', views.user_login, name='user_login'),  # django内置的登录  url(r"^login/$", auth_views.login, name="user_login"),  url(r"^new-login/$", auth_views.login, {"template_name": "account/login.html"}),]

2 测试

希望本文所述对大家基于Django框架的Python程序设计有所帮助。