Mysql 相邻两行记录某列的差值方法

数据库  /  管理员 发布于 7年前   262

表结构：

数据：

需求：

按照company_id不同分组，然后分别求出相同company_id相邻记录touch_time的差值

SQL:

select r1.company_id, r1.touch_time, r2.touch_time, r1.touch_time - r2.touch_time from (select (@rownum := @rownum + 1) as rownum,  info.company_id,  info.touch_time  from sys_touch_info info, (select @rownum := 0) r  where info.touch_time is not null  order by info.company_id) r1 left join (select (@index := @index + 1) as rownum,   info.company_id,   info.touch_time  from sys_touch_info info, (select @index := 0) r  where info.touch_time is not null  order by info.company_id) r2 on r1.company_id = r2.company_id and r1.rownum = r2.rownum - 1

结果：

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