Python制作Windows系统服务

Python  /  管理员 发布于 4年前   336

最近有个Python程序需要安装并作为Windows系统服务来运行，过程中碰到一些坑，整理了一下。

Python服务类

首先Python程序需要调用一些Windows系统API才能作为系统服务，具体内容如下：

#!/usr/bin/env python# -*- coding: utf-8 -*-import sysimport timeimport win32apiimport win32eventimport win32serviceimport win32serviceutilimport servicemanagerclass MyService(win32serviceutil.ServiceFramework):  _svc_name_ = "MyService"  _svc_display_name_ = "My Service"  _svc_description_ = "My Service"  def __init__(self, args):    self.log('init')    win32serviceutil.ServiceFramework.__init__(self, args)    self.stop_event = win32event.CreateEvent(None, 0, 0, None)  def SvcDoRun(self):    self.ReportServiceStatus(win32service.SERVICE_START_PENDING)    try:      self.ReportServiceStatus(win32service.SERVICE_RUNNING)      self.log('start')      self.start()      self.log('wait')      win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)      self.log('done')    except BaseException as e:      self.log('Exception : %s' % e)      self.SvcStop()  def SvcStop(self):    self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)    self.log('stopping')    self.stop()    self.log('stopped')    win32event.SetEvent(self.stop_event)    self.ReportServiceStatus(win32service.SERVICE_STOPPED)  def start(self):    time.sleep(10000)  def stop(self):    pass  def log(self, msg):    servicemanager.LogInfoMsg(str(msg))  def sleep(self, minute):    win32api.Sleep((minute*1000), True)if __name__ == "__main__":  if len(sys.argv) == 1:    servicemanager.Initialize()    servicemanager.PrepareToHostSingle(MyService)    servicemanager.StartServiceCtrlDispatcher()  else:    win32serviceutil.HandleCommandLine(MyService)

pyinstaller打包

pyinstaller -F MyService.py

测试

# 安装服务dist\MyService.exe install# 启动服务sc start MyService# 停止服务sc stop MyService# 删除服务sc delete MyService

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