用PHP获取Google AJAX Search API 数据的代码

php  /  管理员 发布于 7年前   166

http://code.google.com/apis/ajaxsearch/documentation/#fonje

复制代码 代码如下:

// This example request includes an optional API key which you will need to
// remove or replace with your own key.
// Read more about why it's useful to have an API key.
// The request also includes the userip parameter which provides the end
// user's IP address. Doing so will help distinguish this legitimate
// server-side traffic from traffic which doesn't come from an end-user.
$url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&"
. "q=Paris%20Hilton&key=INSERT-YOUR-KEY&userip=USERS-IP-ADDRESS";

// sendRequest
// note how referer is set manually
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, /* Enter the URL of your site here */);
$body = curl_exec($ch);
curl_close($ch);

// now, process the JSON string
$json = json_decode($body);
// now have some fun with the results...

API KEY 申请地址：
http://code.google.com/apis/ajaxsearch/signup.html

由此，我们可以写个函数像这样

复制代码 代码如下:

function google_search_api($args, $referer = '', $endpoint = 'web'){
$url = "http://ajax.googleapis.com/ajax/services/search/".$endpoint;
if ( !array_key_exists('v', $args) )
$args['v'] = '1.0';
$url .= '?'.http_build_query($args, '', '&');
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, $referer);
$body = curl_exec($ch);
curl_close($ch);
return json_decode($body);
}

// 使用示例
$rez = google_search_api(array(
'q' => '21andy.com', // 查询内容
'key' => '你申请到的API KEY',
'userip' => '你的IP地址',
));
header('Content-type: text/html; ');
echo '

'; <br>print_r($rez); <br>echo '';

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