JavaScript实现的3D旋转魔方动画效果实例代码

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JS1K是JavaScript编程竞赛――参加竞赛的规则很简单，脚本必须小于1K，竞赛网站开始也只是为了娱乐，却意外地收到了很多优秀的作品。

这是2016年JS1k上传的作品，用几十行代码实现的一个3D旋转魔方：

代码如下：

function z(t, e) {  return t? e? t.appendChild(e) : "width:"+t+"px;height:"+t+"px;position:absolute;" : document.createElement("div")}function w() {  ++t==360&&(t=0, x=++x%3)  for (i in m) 2 == m[i][s[x]] ? m[i][u][a] = r+s[x]+"(" + t + "deg)" : 0;  c[u][a] = r+"3d(1,1,1," + t + "deg)", requestAnimationFrame(w)}var a = "transform",p = "background-color:",y = a+"-style:preserve-3d;",  u = "style",  v = "cssText",  B = z(),  c = z(),  t = x = 0,  d, e, f, g, h, k, l, m = [], n, i, r="rotate", s = ["X","Y","Z"];B[u][v] = "perspective:900px;"+z(600)+p+"#666";c[u][v] = y + z(240) +"top:30%;left:30%", z(B, c), z(window.b, B);for (l = 27; l--; z(c, f)) {  f = z(),   f[u][v] = y + z(240),   f.X = g = l % 3,   f.Y = h = (l - g) % 9 / 3,   f.Z = k = ~~(l / 9), e = z(),   e[u][v] = y + z(80) +a+":translate3d(" + 80 * g + "px," + 80 * h + "px," + 80 * (k-1) + "px)";  for (n = 6; n--; z(e, d))   d = z(),   d[u][v] = y + z(72) + "border-radius:9px;border:4px solid #000;opacity:0.9;"+a+":"+r+"X(" + (4 > n ? 90 * n : 0)  + "deg)"+r+"Y(" + (4 > n ? 0 : 4 == n ? -90 : 90) + "deg)translateZ(40px);"+p+   (0==n&&2==k?"#05C":1==n&&0==h?"#FD0": 2==n&&0==k?"#0A6":3==n&&2==h?"#FFF":4==n&&0==g?"#F60":5==n&&2==g?"#C24":"#000");  z(f, e), m.push(f)}w();

知识点扩展

JS如何实现旋转的魔方，浏览器从其他标签页回来依然匀速旋转？

          
    
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