python如何实现不用装饰器实现登陆器小程序

Python  /  管理员 发布于 8年前   192

这篇文章主要介绍了python如何实现不用装饰器实现登陆器小程序,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

下面代码演示了不使用装饰器实现用户登陆功能的小程序,在python3.x下可正常运行

#!/usr/bin/env python3# -*- coding: utf-8 -*-"""Created on Tue Nov 26 15:26:58 2019@author: root"""def menu():  print('choice'.center(50,'-'))  msg = '''  1. home  2. finance  3. book  4. exit  '''  print(msg)  print("".center(50,'-')) def login(login_flat,choice):  if not login_flat:    while True:      username = str(input("username:"))      password = str(input("password:"))      if choice == '1':        home()        with open('jingdong.txt','r') as f1:          for line in f1:element = line.split(" ",1)print(element[0])print(element[1])if username.strip() == element[0].strip() and password.strip() == element[1].strip():  print("log in successful!")  return Trueprint("failed to log in!,try it again!")      elif choice == '2':        finance()        with open('weixin.txt','r') as f2:          for line in f1:element = line.split(" ",1)if username.strip() == element[0].strip() and password.strip() == element[1].strip():  print("log in successful!")  return Trueprint("failed to log in!,try it again!")         elif choice == '3':        book()        with open('jingdong.txt','r') as f3:          for line in f3:element = line.split(" ",1)if username.strip() == element[0].strip() and password.strip() == element[1].strip():  print("log in successful!")  return Trueprint("failed to log in!,try it again!")    else:    print("You have logged in before!")    return True#@login(login_flat,choice)def home():  print("home.....")#@login(login_flat,choice) def finance():  print("finance.....")#@login(login_flat,choice) def book():  print("book.....")  login_flag = Falsewhile True:  menu()  choice = input("your choice:")  if choice == '1':    login_flag = login(login_flag,choice)  elif choice == '2':    login_flag = login(login_flag,choice)  elif choice == '3':    login_flag = login(login_flag,choice)  elif choice == '4':    print('bye-bye')    break  else:    print("wrong input ,try it again!")

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