Python Tkinter 简单登录界面的实现

Python  /  管理员 发布于 7年前   189

如下所示：

from tkinter import * class Reg (Frame):  def __init__(self,master):    frame = Frame(master)    frame.pack()    self.lab1 = Label(frame,text = "账户:")    self.lab1.grid(row = 0,column = 0,sticky = W)    self.ent1 = Entry(frame)    self.ent1.grid(row = 0,column = 1,sticky = W)    self.lab2 = Label(frame,text = "密码:")    self.lab2.grid(row = 1,column = 0)    self.ent2 = Entry(frame,show = "*")    self.ent2.grid(row = 1,column = 1,sticky = W)    self.button = Button(frame,text = "登录",command = self.Submit)    self.button.grid(row = 2,column = 1,sticky = E)    self.lab3 = Label(frame,text = "")    self.lab3.grid(row = 3,column = 0,sticky = W)    self.button2 = Button(frame,text = "退出",command = frame.quit)    self.button2.grid(row = 3,column = 3,sticky = E)  def Submit(self):    s1 = self.ent1.get()    s2 = self.ent2.get()    if s1 == 'admin' and s2 == '123':      self.lab3["text"] = "登陆成功"    else:      self.lab3["text"] = "用户名或密码错误!"    self.ent1.delete(0,len(s1))    self.ent2.delete(0,len(s2))root = Tk()root.title("用户登录")app = Reg(root)root.mainloop()

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