Python任意字符串转16, 32, 64进制的方法

Python  /  管理员 发布于 7年前   211

Python字符串转数字

  import binascii  s = 'test123456test'  str_16 = binascii.b2a_hex(s.encode('utf-8')) # 字符串转16进制  print(str_16)  def baseN(num, b):    return ((num == 0) and "0") or \        (baseN(num // b, b).lstrip("0") + "0123456789abcdefghijklmnopqrstuvwxyz"[num % b])  num_10 = int(str_16, 16) # 16进制转10进制  print(num_10)  str_32 = baseN(num_10, 32) # 10进制转32进制  print(str_32)  num_10_2 = int(str_32, 32) # 32进制转10进制  print(num_10_2)  num_16 = hex(num_10) # 10进制转16进制数  print(num_16)  ss = str_16.decode('hex') # 16进制串转字符串  print(ss)

执行结果

746573743132333435367465737423607972896813809817515175175422601q6asrk64p36d1l6pq6asrk23607972896813809817515175175422600x7465737431323334353674657374Ltest123456test

10进制转n进制

def base10toN(num,n):  """Change a to a base-n number.  Up to base-36 is supported without special notation."""  num_rep={10:'a',     11:'b',     12:'c',     13:'d',     14:'e',     15:'f',     16:'g',     17:'h',     18:'i',     19:'j',     20:'k',     21:'l',     22:'m',     23:'n',     24:'o',     25:'p',     26:'q',     27:'r',     28:'s',     29:'t',     30:'u',     31:'v',     32:'w',     33:'x',     34:'y',     35:'z'}  new_num_string=''  current=num  while current!=0:    remainder=current%n    if 36>remainder>9:      remainder_string=num_rep[remainder]    elif remainder>=36:      remainder_string='('+str(remainder)+')'    else:      remainder_string=str(remainder)    new_num_string=remainder_string+new_num_string    current=current/n  return new_num_string

进阶版

  def baseN(num, b):    return ((num == 0) and "0") or \       (baseN(num // b, b).lstrip("0") + "0123456789abcdefghijklmnopqrstuvwxyz"[num % b])

64进制

  def encode_b64(n):    table = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_'    result = []    temp = n    if 0 == temp:      result.append('0')    else:      while 0 < temp:        result.append(table[temp % 64])        temp /= 64    return ''.join([x for x in reversed(result)])  def decode_b64(str):    table = {"0": 0, "1": 1, "2": 2, "3": 3, "4": 4, "5": 5,         "6": 6, "7": 7, "8": 8, "9": 9,         "a": 10, "b": 11, "c": 12, "d": 13, "e": 14, "f": 15, "g": 16,         "h": 17, "i": 18, "j": 19, "k": 20, "l": 21, "m": 22, "n": 23,         "o": 24, "p": 25, "q": 26, "r": 27, "s": 28, "t": 29, "u": 30,         "v": 31, "w": 32, "x": 33, "y": 34, "z": 35,         "A": 36, "B": 37, "C": 38, "D": 39, "E": 40, "F": 41, "G": 42,         "H": 43, "I": 44, "J": 45, "K": 46, "L": 47, "M": 48, "N": 49,         "O": 50, "P": 51, "Q": 52, "R": 53, "S": 54, "T": 55, "U": 56,         "V": 57, "W": 58, "X": 59, "Y": 60, "Z": 61,         "-": 62, "_": 63}    result = 0    for i in xrange(len(str)):      result *= 64      result += table[str[i]]    return result

Java字符串转数字

BigInteger integer = new BigInteger(hexString.toString(), 16);integer.toString(32);

import java.math.BigInteger;public class Main { public static void main(String[] argv) throws Exception {  BigInteger bi = new BigInteger("1023");  bi = new BigInteger("1111111111", 2);   String s = bi.toString(2);   System.out.println(s);  bi = new BigInteger("1000", 8);  System.out.println(s = bi.toString(8));  bi = new BigInteger("1023");   s = bi.toString();   System.out.println(s);  bi = new BigInteger("3ff", 16);   s = bi.toString(16);   System.out.println(s); }}

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