Python基于plotly模块实现的画图操作示例

Python  /  管理员 发布于 7年前   202

本文实例讲述了Python基于plotly模块实现的画图操作。分享给大家供大家参考，具体如下：

import plotlyplotly.tools.set_credentials_file(username='tianjixuetu', api_key='xxxxxxxx')#此处要去官网申请自己的api，#https://plot.ly/ssu/

#案例1import plotly.plotly as pyfrom plotly.graph_objs import *trace0 = Scatter(  x=[1, 2, 3, 4],  y=[10, 15, 13, 17])trace1 = Scatter(  x=[1, 2, 3, 4],  y=[16, 5, 11, 9])data = Data([trace0, trace1])py.plot(data, filename = 'basic-line')

#案例2import plotly.graph_objs as goimport plotly.plotly as pyimport numpy as npcolorscale = [[0, '#FAEE1C'], [0.33, '#F3558E'], [0.66, '#9C1DE7'], [1, '#581B98']]trace1 = go.Scatter(  y = np.random.randn(500),  mode='markers',  marker=dict(    size='16',    color = np.random.randn(500),    colorscale=colorscale,    showscale=True  ))data = [trace1]url_1 = py.plot(data, filename='scatter-for-dashboard', auto_open=False)py.iplot(data, filename='scatter-for-dashboard')url_1

#案例3import plotly.plotly as pyimport plotly.graph_objs as goimport numpy as npx0 = np.random.randn(50)x1 = np.random.randn(50) + 2x2 = np.random.randn(50) + 4x3 = np.random.randn(50) + 6colors = ['#FAEE1C', '#F3558E', '#9C1DE7', '#581B98']trace0 = go.Box(x=x0, marker={'color': colors[0]})trace1 = go.Box(x=x1, marker={'color': colors[1]})trace2 = go.Box(x=x2, marker={'color': colors[2]})trace3 = go.Box(x=x3, marker={'color': colors[3]})data = [trace0, trace1, trace2, trace3]url_2 = py.plot(data, filename='box-plots-for-dashboard', sharing='public', auto_open=True,world_readable=True)py.iplot(data, filename='box-plots-for-dashboard')url_2

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希望本文所述对大家Python程序设计有所帮助。