python3爬取数据至mysql的方法

Python  /  管理员 发布于 7年前   148

本文实例为大家分享了python3爬取数据至mysql的具体代码，供大家参考，具体内容如下

直接贴代码

#!/usr/local/bin/python3.5 # -*- coding:UTF-8 -*- from urllib.request import urlopen from bs4 import BeautifulSoup import re import datetime import random import pymysql  connect = pymysql.connect(host='192.168.10.142', unix_socket='/tmp/mysql.sock', user='root', passwd='1234', db='scraping', charset='utf8') cursor = connect.cursor() cursor.execute('USE scraping')  random.seed(datetime.datetime.now())   def store(title, content):    execute = cursor.execute("select * from pages WHERE `title` = %s", title)   if execute <= 0:     cursor.execute("insert into pages(`title`, `content`) VALUES(%s, %s)", (title, content))     cursor.connection.commit()   else:     print('This content is already exist.')   def get_links(acticle_url):   html = urlopen('http://en.wikipedia.org' + acticle_url)   soup = BeautifulSoup(html, 'html.parser')   title = soup.h1.get_text()   content = soup.find('div', {'id': 'mw-content-text'}).find('p').get_text()   store(title, content)   return soup.find('div', {'id': 'bodyContent'}).findAll('a', href=re.compile("^(/wiki/)(.)*$"))  links = get_links('')  try:   while len(links) > 0:     newActicle = links[random.randint(0, len(links) - 1)].attrs['href']     links = get_links(newActicle)     print(links) finally:   cursor.close()   connect.close() 

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