Python3调用微信企业号API发送文本消息代码示例

Python  /  管理员 发布于 7年前   328

本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：

#!/usr/bin/env python# -*- coding:utf-8 -*-import urllib.requestimport jsonimport sysimport loggingtouser = '@all'agentid = 0corpid = 'wx5aef2da956514535'corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'url = 'https://qyapi.weixin.qq.com'subject = sys.argv[2]message = sys.argv[3]logging.basicConfig(level=logging.DEBUG, filename='E:\Python_project\Scripts\my.log',          format='%(asctime)s - %(levelname)s: %(message)s')class Weixin:  def __init__(self, url, corpid, corpsecret):    token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url, corpid, corpsecret)    self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']  def send_message(self, url, data):    send_url = '%s/cgi-bin/message/send?access_token=%s' % (url, self.token)    self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url, data=data)).read()    x = json.loads(self.respone.decode())['errcode']    if x == 0:      logging.debug('Successfully %s  %s' % (subject, message))      return 'Succesfully'    else:      logging.debug('Failed %s  %s' % (subject, message))      return 'Failed'  def messages(self, subject, message):    values = {      "touser": touser,      "msgtype": 'text',      "agentid": agentid,      "text": {'content': subject + message},      "safe": 0    }    return self.send_message(url, bytes(json.dumps(values), 'utf-8'))if __name__ == '__main__':  obj = Weixin(url, corpid, corpsecret)  ret = obj.messages(subject, message)

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