通过构造AJAX参数实现表单元素JSON相互转换

微信(小程序)  /  管理员 发布于 3年前   149

ajax提交服务器数据， 整理一下转换方法。

HTML：

<form id="fm" name="fm" action=""><input name="UserName" type="text" value="UserName1"/></form><input name="UserId" id="UserId" type="text" value="UserId1"/> 

1.表单元素转QueryString

var q = $('#fm,#UserId').serialize(); //q = UserName=UserName1&UserId=UserId1 

2.字符串， JSON 互相转换

var obj = jQuery.parseJSON('{"name":"John"}');alert( obj.name === "John" ); 

可以利用jquery-json插件实现转换，直接引用示例

var thing = {plugin: 'jquery-json', version: 2.3};var encoded = $.toJSON( thing );// '{"plugin":"jquery-json","version":2.3}'var name = $.evalJSON( encoded ).plugin;// "jquery-json"var version = $.evalJSON(encoded).version;// 2.3 

3.表单，元素转Name,Value数组

var arr = $("#fm,#UserId").serializeArray();/*[ {name: 'UserName', value: '"UserName"1'}, {name: 'UserId', value: 'UserId'}] */ 

4. 表单元素转JSON

$.fn.serializeObject = function(){var o = {};var a = this.serializeArray();$.each(a, function() {if (o[this.name] !== undefined) {if (!o[this.name].push) {o[this.name] = [o[this.name]];}o[this.name].push(this.value || '');} else {o[this.name] = this.value || '';}});return o;};var obj = $('form').serializeObject();/*obj: ObjectUserId: "UserId1"UserName: "UserName1"__proto__: Object*/ 

5. JSON2FORM

$.getJSON('url_to_file', function(data) {for (var i in data) {$('input[name="'+i+'"]').val(data[i]);}}

Google过程中发现一个更强大的插件 http://code.google.com/p/jquery-load-json/

data = {"Name":"Emkay Entertainments","Address":"Nobel House, Regent Centre","Contact":"Phone"} $('div#data').loadJSON(data);<div id="data"><h1 id="Name">Emkay Entertainments</h1><label for="Address">Address:</label><span id="Address">Nobel House, Regent Centre</span> <label for="Contact">Contact by:</label><span id="Contact">Phone</span></div>