Python字典实现简单的三级菜单(实例讲解)

Python  /  管理员 发布于 7年前   221

如下所示：

data = { "北京":{  "昌平":{"沙河":["oldboy","test"],"天通苑":["链接地产","我爱我家"]},  "朝阳":{"望京":["奔驰","陌陌"],"国贸":["CICC","HP"],"东直门":["advent","飞信"]},  "海淀":{} }, "山东":{  "德州":{},  "青岛":{},  "济南":{} }, "广东":{  "东莞":{},  "常熟":{},  "佛山":{} }}exit_flag = Falsewhile not exit_flag: for i in data:  print(i) choice_s = input("请输入以上任一省或直辖市名称>>>:") if choice_s in data:  while not exit_flag:   for i in data[choice_s]:    print("\t",i)   choice_q = input("请输入以上任一市区名称>>>:")   if choice_q in data[choice_s]:    while not exit_flag:     for i in data[choice_s][choice_q]:      print("\t\t",i)     choice_j = input("请输入以上任一街道名称>>>:")     if choice_j in data[choice_s][choice_q]:      for i in data[choice_s][choice_q][choice_j]:       print("\t\t",i)      last = input("最后一层，按b返回>>>:")      if last == "b":       pass      elif last == "q":       exit_flag = True     if choice_j == "b":      break     elif choice_j == "q":      exit_flag = True   if choice_q == "b":    break   elif choice_q == "q":    exit_flag = True

要点：

1、字典的层级关系

2、break是终止本次循环，pass是什么也不做，一个占位符而已

3、巧妙使用exit_flag = False

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