Python 解码Base64 得到码流格式文本实例

Python  /  管理员 发布于 7年前   182

我就废话不多说了，直接上代码吧！

# coding:utf8import base64  def BaseToFlow():  while True:    str = input("Please input src: ")    flag = input("Please input Decode - 1 or Encode - 2: ")    if str == "":      str = "ApIAGBcEAAAEBO6x3nLykEEhjWMX1wHs"    if flag == "":      flag = "1"    if flag == "1":      print("Decoding ...")      dst = base64.b64decode(str)      # print(type(dst))      # <class 'bytes'>      # print(dst)      # b'\x02\x92\x00\x18\x17\x04\x00\x00\x04\x04\xee\xb1\xder\xf2\x90A!\x8dc\x17\xd7\x01\xec'      # print(dst.hex()) --去掉\0x前缀 得到一个字符串      # 02920018170400000404eeb1de72f29041218d6317d701ec      HexFormat(dst.hex())    elif flag == "2":      print("Encoding ...")      dst = base64.b64encode(str)      print(dst)  def HexFormat(str):  """  :param str: 16进制连续字符串  :return: 码流格式的16进制串  """  i = 1  str2 = ""  while (i <= len(str)):    str2 = str2 + str[i - 1] + str[i] + " "    if (i + 1) %16 == 0 and (i + 1) % 32 != 0:      str2 = str2 + " "    elif (i + 1) %32 == 0:      str2 = str2 + "\n"    i = i + 2  if __name__ == '__main__':  BaseToFlow()

结果：

Please input src: Please input Decode - 1 or Encode - 2: Decoding ...02 92 00 18 17 04 00 00 04 04 ee b1 de 72 f2 90 41 21 8d 63 17 d7 01 ec 

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