python matplotlib拟合直线的实现

Python  /  管理员 发布于 7年前   173

这篇文章主要介绍了python matplotlib拟合直线的实现,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

代码如下

import numpy as npimport matplotlib.pyplot as pltplt.rcParams['font.family'] = ['sans-serif']plt.rcParams['font.sans-serif'] = ['SimHei']def linear_regression(x, y):  N = len(x)  sumx = sum(x)  sumy = sum(y)  sumx2 = sum(x ** 2)  sumxy = sum(x * y)  A = np.mat([[N, sumx], [sumx, sumx2]])  b = np.array([sumy, sumxy])  return np.linalg.solve(A, b)#单臂#修改数据1：X1=np.array([0,20,40,60,80,100,120,140,160,180,200])Y1=np.array([0,0.02,0.06,0.1,0.13,0.16,0.19,0.22,0.245,0.278,0.3])#半桥#修改数据2：X2=np.array([0,20,40,60,80,100,120,140,160,180,200])Y2=np.array([0,0.057,0.118,0.185,0.245,0.308,0.376,0.425,0.488,0.544,0.58])a0, a1 = linear_regression(X1, Y1)# 生成拟合直线的绘制点_X1 = [0, 200]_Y1 = [a0 + a1 * x for x in _X1]a0, a1 = linear_regression(X2, Y2)# 生成拟合直线的绘制点_X2 = [0, 200]_Y2 = [a0 + a1 * x for x in _X1]#显示图像plt.plot( X1, Y1, 'ro', linewidth=2,label="单臂电桥")plt.plot(_X1, _Y1, 'b',linewidth=2,label='单臂电桥',color='C0')plt.plot( X2, Y2, 'g^', linewidth=2,label='半桥')plt.plot(_X2, _Y2, 'b', linewidth=2,label='半桥',color='C1')plt.xlabel('weight/g')plt.ylabel('voltage/v')plt.legend()plt.show()

图例

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