python利用7z批量解压rar的实现

Python  /  管理员 发布于 7年前   350

一开始我使用了rarfile这个库，奈何对于含有密码的压缩包支持不好，在linux上不抛出异常；之后有又尝试了unrar。。比rarfile还费劲。。

所以用了调用系统命令的方法，用7z来解压

通过apt可以安装上7z-full和7z的rar插件

有一个地方要注意 -o 和-p与后面的目录、密码之间没有空格！！

同样可以用这个代码暴力破解压缩包密码

# coding:utf-8 import osimport zipfileimport tracebackimport timeimport shutilimport sys,getopt succeedpath=""unsucceedpath=""psds={"2018","123456"}  opts,args=getopt.getopt(sys.argv[1:],"p:")path=args[0]for psd in args[1:]:  psds.add(psd)#for op,value in opts:#  if op in ("-p","--password"):#    psds.add(value)  def mkdirs(dirpath):  global succeedpath,unsucceedpath  succeedpath=os.path.join(dirpath,"0.succeed")  unsucceedpath=os.path.join(dirpath,"0.unsucceed")  if(not os.path.exists(succeedpath)):    os.makedirs(succeedpath)  if(not os.path.exists(unsucceedpath)):    os.makedirs(unsucceedpath) def extractdir(path):  for filename in os.listdir(path):    filepath=os.path.join(path,filename)    if(os.path.isfile(filepath)):      extractfile(filepath)  def extractfile(path):  (dirpath,filen)=os.path.split(path)  print("解压"+filen+"   ing...")  try:    if(filen.endswith(".rar") or filen.endswith(".zip")):      path=os.path.abspath(path)      dirpath=os.path.abspath(dirpath)      cmd="7z x "+path+" -o"+dirpath+" -y "+" -p"      state=False      if(os.system(cmd)==0):        state=True      else:        for psd in psds:          cmdp="7z x "+path+" -p"+psd+" -y "+" -o"+dirpath          if(os.system(cmdp)==0):state=Truebreak    else:      return    if (state):      shutil.move(path,succeedpath)    else:      shutil.move(path,unsucceedpath)      with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo:        errorinfo.write("time:"+str(time.time())+"\n")        errorinfo.write("解压出错！\n可能是密码错误！\n")  except :    with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo:      errorinfo.write("time:"+str(time.time())+"\n")      errorinfo.write("解压出错！\n")      traceback.print_exc(file=errorinfo)    shutil.move(path,unsucceedpath) if(os.path.isdir(path)):  dirpath=path  mkdirs(dirpath)  extractdir(dirpath)elif(os.path.isfile(path)):  filepath=path  (dirpath,filename)=os.path.split(path)  mkdirs(dirpath)  extractfile(path)else:  print("输入错误！请重新输入！")

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